
David Garrard Named AFC Offensive Player-of-the-Week
December 07, 2006 | Football
Dec. 7, 2006
JACKSONVILLE, Fla. - Jaguars quarterback David Garrard was named by the NFL the AFC Offensive Player of the Week league officials announced on Tuesday. He completed 16 of 22 passes for 229 and two touchdowns and led the Jaguars (7-5) to a 24-10 road win over the Dolphins in Miami.
Garrard completed 72.7 percent of his pass attempts without an interception for a career-best 136.4 passer rating. The victory lifted Jacksonville to 7-5 and snapped the Dolphins' four-game winning streak. In addition to his passing, Garrard ran six times for 24 yards including three first downs. He connected on a 16-yard touchdown pass to tight end George Wrighster for a 17-7 lead just before halftime. The East Orange, N.J. native directed the club on two drives of more than 90 yards, both resulting in touchdowns. Ten of Garrard's 16 completions resulted in first-downs as he improved to 9-5 overall as a starter, winning eight of his last 11 starts.
In his fifth season from East Carolina, this is the Garrard's first Player of the Week honor. He is the first Jaguars player to win Player of the Week honors since Rashean Mathis won defensive honors in Week Two.